MIDI Forum

These numbers indeed are wrong for a male plug. Does this thing have a name and/or a datasheet?

Just for completeness, an image (front/external side for female/socket; solder/internal side for male/plug). DIN-41524.png

A quick web search shows that "JS: Utility / Volume" does support MIDI learn, but MLimiterFree probably does not.

Yes; the reset SysExs reset everything.

Your suspicions are correct; the Reset must come first. Apparently, Cakewalk does not recognize the dependencies of the All Notes Off/Reset All Cont...

That file is indeed damaged; a zero byte at the end was missing. In general, you'd have to load the file in a sequencer (hoping that it is as toler...

Correct. If each letter in "LRcccddd" represents one bit, then the data bytes in the SysEx message would be "0000cddd 0000LRcc", and to set the fee...

If you send zero bits, then those values will be set to zero. If you do not want to change tha values, you have to send the old values. If you do n...

You can change the parameters and then send the entire memory dump. Doing this when you want to change only a single parameter is what I call "not fea...

[quotePost id=20655br /> That is not a MIDI cable. (It is not possible to split MIDI signals this way.) That seller tried to include as many keywo...

As far as I can see, there is no memory address in the message, so I guess it expects you to transmit the entire memory contents. In other words, it i...

The 7th byte consists of two fields, 7 bits for the cutoff, and 1 bit for the trigger mode. If the cutoff is 21 (0010101), and the trigger mode is 1, ...

The electrical specification says: The cable shall be shielded twisted pair, with the shield connected only to pin 2 at both ends, as illustrated in ...

The fifth byte must be 00011xxx, i.e., between 18 and 1F. The sixth byte must be between 40 and 7F. What you write as "pp" must be two bytes, each b...

The first byte must be not F7 but F0.